Solve a linear equation and Quadratic equation (2)



Example 1:
Solve the following equations
X + y = 8   , x y – 15  = 0
the answer :
from the first equation :
 y = 8 – x 
Substitute the expression 8 – x  for y into the second equation and solve for x
X ( 8 – x ) – 15 = 0
8 x – x2 – 15 = 0  …….. ×   - 1 
X2 – 8 x + 15 =0
( x – 3 ) ( x – 5 ) = 0
x = 3                              or               x = 5
y = 8 - x =8 - 3                                y = 8 -x =8 - 5
y= 5                                                  y= 3
the solution to this equations = {(3, 5) ,( 5 , 3) }

Example 2:
Solve the following equations
X + y = 7   , x y – 12 = 0
the answer :
from the first equation : y = 7 – x 
Substitute the expression 7 – x  for y into the second equation and solve for x
X ( 7 – x ) – 12= 0
 …………..
…………….
the solution to this equations = {(3, 4) ,( 4 , 3) }

Example 3 :
Solve the following equations
X + y = 10   , x y = 16   
the answer :
from the first equation : y = 10 – x 
Substitute the expression 10 – x  for y into the second equation and solve for x
X ( 10 – x ) – 16 = 0
10 x – x2 – 16 = 0  …….. ×   - 1 
X2 – 10 x + 16 =0
 …………..
the solution to this equations = {(2, 8) ,( 8 , 2) }

Example 4:
Solve the following equations
X = y  ,  x2 + y2  = 50
the answer :
Substitute x for y into the second equation and solve for x
 X2 + x2 = 50
2 x2  = 50
X2 =25
x = 5                              or           x = - 5
y =  x                                            y =  x     
y= 5                                              y= -  5
the solution to this equations = { (5, 5) , ( - 5 , - 5 ) }

Example 5 :
Solve the following equations
X + y = 6   , x2    y2  = 24
the answer :
from the first equation : x = 6 – y 
Substitute the expression 6 – y  for x into the second equation and solve for y
  ( 6 – y )2  – y2  = 24
36 – 12 y + y2 – y2  = 24
- 12 y = -36 + 24
- 12 y = -12
 Y = 1
X + y = 6
x  + 1 = 6
x = 5                                            

the solution to this equations = {(5, 1) }

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