the method of elimination""
Example 1: Solve the following equations
x+ y = 5
, 2x –3 y = 10
the answer :
2x – 3y = 10 ………..×1
3 x + 3 y = 15
2 x – 3 y = 10 add
5 x = 25
X=25 /5
X =5
Put value of x
in the first equation to get value of y
x+ y= 5
5 + y = 5
Y =5 – 5
Y = 0
the solution to this equations = {(5 , 0)}
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Example 2:Solve the following equations
X + y = 4 ………. ×2
2 x + 2 y = 8
3 x – 2 y = 7 add
5 x = 15
X = 3
………..
the same ……….
the solution to this equations = {(3, 1)}
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Example 3 :Solve the following equations
X + y = 5 ………
×4
x –
4 y = 10 ………×1
4 x + 4 y = 20
X - 4
y = 10
…………..
the same ……….
the solution to this
equations = {(6,-1)}
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Example 4: Two numbers equal to 7 , four times the first number is greater than three
times of the second by 14
Find the two numbers
the answer :
let the two numbers is X and y
then :
x + y =7
……….. ×3
4x – 3 y = 14 ……….. ×1
3 x + 3 y = 21
4 x - 3 y
= 14
7 x =
………
X = ….
the same……….
The two numbers is 5 , 2
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Example 5 :
Solve the following
equations
X + 2 y = 7 …………
×3
x – 3
y = 2 …….……×2
3 x + 6 y = 21
2 X - 6y = 4
5 x = 25
X = 5
5 + 2 y = 7
2 y = 7 – 5
2 y = 2
Y = 1
the solution to this
equations = {(5, 1)}


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